C PROGRAM FOR ARMSTRONG NUMBER

/*  C PROGRAM FOR  ARMSTRONG NUMBER */

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

     int s,x,i,n;

     clrscr();

     printf("\n\t\tARMSTRONG NUMBER");

     printf("\n\t\t~~~~~~~~~~~~~~~~");

     printf("Armstrong no's are\n");

       for(i=100;i<=1000;i++)

      {

         s=0;

         x=i;

          while(x>0)

          {

              n=x%10;                      

              x=x/10;                  

               s+=pow(n,3);             

           }                       

            if(i==s)                

            printf("%d\n\n",i);     

       }                       

     getch();

}                     

             

OUTPUT:

ARMSTRONG NUMBER

  

 Armstrong no's are:

153

370

371

407