C PROGRAM FOR REPLACING STRING

/* C PROGRAM FOR  REPLACING STRING*/

#include<stdio.h>

#include<conio.h>

#include<string.h>

 void main()

 {

          int slen,sublen,newlen,reslen,m,k,i,j,temp;

          char str[40],substr[20],newstr[20],resstr[25];

          clrscr();

          printf("\n\t\t STRING REPLACING");

          printf("\n\t\t ~~~~~~~~~~~~~~~~~");

          printf("\n Enter any string:");

          gets(str);

          slen=strlen(str);

          printf("\n Enter the substring:");

          gets(substr);

          sublen=strlen(substr);

          printf("\n Enter the replacement string:");

          gets(resstr);

          reslen=strlen(resstr);

          j=0;

          k=0;

for(i=0;i<slen;i++)

{

         newstr[k]=str[i];

         k++;

         if(str[i]==substr[j])

         j++;

else

         j=0;

if(j==sublen)

{

         k=k-sublen;

         j=0;

for(m=0;m<reslen;m++)

{

         newstr[k]=resstr[m];

         k++;

     }

   }

}

      newstr[k]='\0';

      printf("\n The replaced string is %s",newstr);

      getch();

}

OUTPUT:

                 STRING REPLACING

                 ~~~~~~~~~~~~~~~~~

 Enter any string: RAJ

 Enter the substring: R

 Enter the replacement string: T

 The replaced string is: TAJ

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C PROGRAM FOR SALES REPORT

/*  C PROGRAM FOR  SALES REPORT */

#include<stdio.h>

#include<conio.h>

#include<string.h>

void main()

{

     int sal[5][5],s,p,i,j,row,col,temp,per,avg;

     char s_men[10][30],pr[10][30],waste[33];

     clrscr();

     printf("\n\t\t SALES REPORT");

     printf("\n\t\t -------------");

     printf("Enter how many salesman:");

     scanf("%d",&s);

     printf("Enter how many products:");

     scanf("%d",&p);

     clrscr();

     gets(waste);

for(i=1;i<=s;i++)

{

     printf("\n Enter the %d name of salesman:",i);

     gets(s_men[i]);

 }

for(j=1;j<=p;j++)

{

     printf("\n Enter the %d name of products:",j);

     gets(pr[j]);

}

for(i=1;i<=s;i++)

for(j=1;j<=p;j++)

     sal[i][j]=0;

     clrscr();

     printf("\n\t The salesman and products data:");

while(1)

{

     clrscr();

for(i=1;i<=s;i++)

     printf("\n%d salesman :%s",i,s_men[i]);

for(i=1;i<=p;i++)

{

      gotoxy(35,i+1);

      printf("%d Products:%s",i,pr[i]);

}

    

     gotoxy(5,10);

     printf("\n\n Enter which salesman connected with which products");

     printf("\n Enter the salesman no");

     scanf("%d",&row);

     printf("\n Enter the product no:");

     scanf("%d",&col);

     printf("\n Enter the sales rupees:");

     scanf("%d",&per);

     sal[row][col]=per;

     printf("\n\n Do you want to continue (1 for yes,2 for no):\n");

     scanf("%d",&temp);

     if(temp==1)

     continue;

     else

     break;

  }

  clrscr();

  printf("\n\n The salesman and products report:\n\n");

  gotoxy(8,5);

for(i=1;i<=p;i++)

   printf("\t Products %d",i);

   printf("\n");

for(i=1;i<=s;i++)

{

    printf("Salesman %d",i);

for(j=1;j<=p;j++)

    printf("\t%2d\t",sal[i][j]);

    printf("\n\n");

 }

    printf("\n\t Total details:");

for(i=1;i<=s;i++)

{

    avg=0;

for(j=1;j<=p;j++)

    avg=avg+sal[i][j];

    printf("\n The total rupees sold by salesman %d is %d",i,avg);

   }

 getch();

}

OUTPUT:

SALES REPORT

Enter how many salesmen:

Enter how many salesmen: 2

Enter how many products: 2

 Enter the 1 name of salesman: Raj

 Enter the 2 name of salesman: krk

 Enter the 1 name of products: bat

 Enter the 2 name of products: ball

1 salesman: raj                  1 Products: bat

2 salesmen: krk                  2 Products: ball

 Enter which salesman connected with which products:

Enter the salesman no: 1

Enter the product no: 1

Enter the sales rupees: 1000

Do you want to continue (1 for yes, 2 for no): 1

 Enter which salesman connected with which products

 Enter the salesman no: 2

 Enter the product no: 2

 Enter the sales rupees: 500

Do you want to continue (1 for yes, 2 for no): 2

 The salesman and products report:

                    Products 1           Product 2

Salesman 1      1000                     0

Salesman 2         0                       500

       

 Total details:

 The total rupees sold by salesman 1 is 1000

 The total rupees sold by salesman 2 is 500

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C PROGRAM FOR BOOK SEARCHING AND SORTING

/* C PROGRAM FOR BOOK SEARCHING AND SORTING*/

#include<stdio.h>

#include<conio.h>

#include<string.h>

void newentry();

void sort();

void search();

void list();

struct books

{

    char authname[50];

    char title[50];

}b[10];

int c=1;

void main()

{

int k,i,ch,n;

char w[30];

clrscr();

printf("\n\t\t\tBOOK OPERATION\n");

printf("\n\t\t\t--------------\n");

printf("\nEnter how many book you want to enter:");

scanf("%d",&n);

for(i=0;i<n;i++)

newentry();

while(1)

{

 clrscr();

 printf("\nMain Menu");

 printf("\n1.Newentry\n");

       printf("\n2.Search");

       printf("\n3.Sort");

       printf("\n4.List");

       printf("\n5.Exit\n");

       printf("\nEnter your choice:");

       scanf("%d",&ch);

switch(ch)

{

 case 1:

                   newentry();

                         break;

       case 2:

                   search();

                   break;

       case 3:

                   sort();

                   break;

       case 4:

                   list();

                   break;

       case 5:

                   exit();

            break;

}

}

}

void search()

{

char tit[44],w[22],d,authname[44];

int i,a=0,z;

clrscr();

gets(w);

printf("\nDo you want to search using author name(Y/N)!");

scanf("%c",&d);

if(d=='y'||d=='n')

{

gets(w);

printf("\nEnter any author name you want to search:");

gets(authname);

for(i=0;i<=c;i++)

{

z=strcmp(authname,b[i].authname);

if(z==0)

{

printf("\n\nThe book have been found");

printf("\n\nThe book title is %s", b[i].title);

printf("\n\nThe book author name is : %s",b[i].authname);

a=1;

}

}

if(a==0)

printf("\n\nThe book was not found:");

}

getch();

}

void sort()

{

char temp[50],t_tit[44][44];

int i,j,z;

clrscr();

printf("\nThe Sorted book are");

for(i=0;i<=c;i++)

strcpy(t_tit[i],b[i].title);

for(i=0;i<=c;i++)

{

for(j=0;j<=c;j++)

{

z=strcmp(t_tit[i],t_tit[j]);

if(z>0)

{

strcpy(temp,t_tit[i]);

strcpy(t_tit[i],t_tit[j]);

strcpy(t_tit[j],temp);

}

}

}

for(i=0;i<=c;i++)

printf("%s\n",t_tit[i]);

getch();

}

void newentry()

{

char titles[20],author[50],was[22];

clrscr();

gets(was);

c++;

printf("Enter any author:");

gets(b[c].authname);

printf("Enter any title:");

gets(b[c].title);

printf("%s",b[c].title);

printf("\n%s",b[c].authname);

printf("\n%s",b[c].authname);

getch();

}

void list()

{

int i;

clrscr();

printf("AUTHOR NAME  \t\tTITLES");

for(i=0;i<=c;i++)

printf("\n\n%s\t\t%s",b[i].authname,b[i].title);

getch();

}

OUTPUT

BOOK OPERATION

                                               

Enter how many book you want to enter: 2

Enter any author: R.Balaguruswamy

Enter any title: Programming in C

Programming in C

R.Balaguruswamy

Enter any author: Morris Mano

Enter any title: Computer System Architecture

Computer System Architecture

Morris Mano

Main Menu

1. New entry

2. Search

3. Sort

4. List

5. Exit

Enter your choice: 1

Enter any author: Problem Solving Techniques

Enter any title:  R.G.Dromey

Problem Solving Techniques

R.G.Dromey

Main Menu

1. New entry

2. Search

3. Sort

4. List

5. Exit

Enter your choice: 2

Do you want to search using author name(Y/N)!  Y

Enter any author name you want to search: R.Balaguruswamy

The book have been found

The book title is Programming in C

The book author name is: R.Balaguruswamy

Main Menu

1. New entry

2. Search

3. Sort

4. List

5. Exit

Enter your choice: 2

Do you want to search using author name(Y/N)!  Y

Enter any author name you want to search: Richard hall

The book was not found

Main Menu

1. New entry

2. Search

3. Sort

4. List

5. Exit

Enter your choice: 3

The Sorted books are

Programming in C

Problem Solving Techniques

Computer System Architecture

Main Menu

1. New entry

2. Search

3. Sort

4. List

5. Exit

Enter your choice: 4

AUTHOR NAME                              TITLES

----------------------                              ----------

R.Balaguruswamy                      Programming in C

Morris Mano                              Computer System Architecture

R.G.Dromey                               Problem Solving Techniques

Main Menu

1. New entry

2. Search

3. Sort

4. List

5. Exit

Enter your choice: 5

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C PROGRAM FOR BANK OPERATION USING FUNCTIONS

/* C PROGRAM FOR  BANK OPERATION USING FUNCTIONS*/

#include<stdio.h>

#include<conio.h>

int amt=10000,b,w,d,n;

void deposit()

{

     printf("Enter amount\n");

     scanf("%d",&d);

     amt=amt+d;

     printf("Your amount is:%d\n",amt);

 }

void withdraw()

{

     printf("Enter amount\n");

     scanf("%d",&w);

     if(amt>=100)

     {

      amt=amt-w;

      printf("Your amt is:%d\n",amt);

     }

     else

     printf("You have below 100 Rs\n");

}

void balance()

{

      printf("The balance amount is :%d\n",amt);

 }

void main()

{

      int ba;

      clrscr();

      printf("\t\t BANKING OPERATION USING FUNCTION \n\n");

      printf("1.Deposit\n2.Withdraw\n3.Balance\n4.Exit\n");

     do

    {

       printf("\n Enter any choice:");

        scanf("%d",&ba);

        switch(ba)

        {

          case 1:

                    deposit();

                    break;

          case 2:

                    withdraw();

                     break;

          case 3:

                    balance();

                    break;

          case 4:

                        getch();

                        break;

       }

    }while(ba!=4);

     getch();

}

OUTPUT:

                 BANKING OPERATION USING FUNCTION

1. Deposit

2. Withdraw

3. Balance

4. Exit

 Enter any choice: 1

Enter amount:

1200

Your amount is: 11200

 Enter any choice: 2

Enter amount:

11200

Your amt is: 0

 Enter any choice: 2

Enter amount:

1000

You have below 100 rs

 Enter any choice: 1

Enter amount:

15000

Your amount is: 15000

 Enter any choice: 3

The balance amount is: 15000

 Enter any choice: 4

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C PROGRAM FOR STUDENTS MARKSHEET USING STRUCTURES

/*  C PROGRAM FOR STUDENTS MARKSHEET USING STRUCTURES */

#include<stdio.h>

#include<conio.h>

struct stu

{

      int rn,grade,a[5];

      float avg;

  }s[2];

void main()

{

      int i,j,sum,n;

      float avg;

      clrscr();

      printf("\t STUDENT MARKSHEET USING STRUCTURES\n\n");

      printf("Enter the no of students");

      scanf("%d",&n);

for(i=0;i<n;i++)

{

      scanf("%d",s[i].rn);

for(j=0;j<=5;j++)

{

      scanf("%d",&s[i].a[j]);

   }

 }

for(i=0;i<n;i++)

{

       sum=0;

for(j=0;j<5;j++)

{

        sum=sum+s[i].a[j];

        s[i].avg=(float)(sum/5);

        if(s[i].avg>=60)

        s[i].grade=1;

        else if(s[i].avg>50&&s[i].avg<60)

        s[i].grade=2;

else

       s[i].grade=3;

  }

}

       printf("****************************************\n");

       printf("rn\ts1\ts2\ts3\ts4\ts5\tavg\t grade\n");

       printf("*****************************************\n");

for(i=0;i<n;i++)

{

       printf("%d\t",s[i].rn);

for(j=0;j<5;j++)

{

       printf("%d\t",s[i].a[j]);

    }

      printf("%f\t%d\n",s[i].avg,s[i].grade);

  }

  getch();

}

OUTPUT:

STUDENTS MARKSHEET USING STRUCTURES

 

Enter the no of students: 5

1

89        90        90        99        82

2

67        73        77        60        88

3

56        54        59        76        66

4

45        44        56        34        65

5

56        76        90        85        64

*********************************************************

Rn       s1        s2         s3         s4         s5         avg                  grade

*********************************************************

1          89        90        90        99        82        90.000000           1

2          67        73        77        60        88        71.000000           1

3          56        54        53        76        66        62.000000           1

4          45        44        56        34        65        48.000000           3

5          56        76        90        35        64        74.000000           1

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C PROGRAM FOR TOWERS OF HANOI

/* C PROGRAM FOR  TOWERS OF HANOI */

#include<stdio.h>

#include<conio.h>

void transfer(int t,char,char,char);

void main()

{

      int n;

      clrscr();

      printf("\n\n\t\t TOWERS OF HANOI");

      printf("\n\n\t\t ~~~~~~~~~~~~~~~~");

      printf("\n\n Enter the no of disk:");

      scanf("%d",&n);

      transfer(n,'l','r','c');

      getch();

  }

void transfer(int n,char from,char to,char temp)

{

if(n>0)

{

       transfer(n-1,from,temp,to);

       printf("\n Move disk %d From %c To %c",n,from,to);

       transfer(n-1,temp,to,from);

    }

 }

OUTPUT:

                 TOWERS OF HANOI

                 ~~~~~~~~~~~~~~~~

 Enter the no of disk:4

 Move disk 1 From l To c

 Move disk 2 From l To r

 Move disk 1 From c To r

 Move disk 3 From l To c

 Move disk 1 From r To l

 Move disk 2 From r To c

 Move disk 1 From l To c

 Move disk 4 From l To r

 Move disk 1 From c To r

 Move disk 2 From c To l

 Move disk 1 From r To l

 Move disk 3 From c To r

 Move disk 1 From l To c

 Move disk 2 From l To r

 Move disk 1 From c To r

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C PROGRAM FOR PRIME NUMBER GENERATION

/* C PROGRAM FOR  PRIME NUMBER GENERATION */

#include<stdio.h>

#include<conio.h>

void main()

{

             int a,b,c=0,r;

 clrscr();

             printf("\n\t\tPRIME NUMBER");

             printf("\n\t\t~~~~~~~~~~~~~");

             printf("\nEnter range:");

             scanf("%d",&r);

             a=1;

            while(a<=r)

             {

                   b=1;c=0;

                   while(b<=a)

                   {

                      if(a%b==0)

                       c=c+1;

                       b++;

                   }           

             if(c==2)

             printf("\n %d is a prime number",a);

             a++;

           }

          getch();

}

         

OUTPUT:

      PRIME NUMBER

                ~~~~~~~~~~~~~

Enter range: 50

 2 is a prime number

 3 is a prime number

 5 is a prime number

 7 is a prime number

 11 is a prime number

 13 is a prime number

 17 is a prime number

 19 is a prime number

 23 is a prime number

 29 is a prime number

 31 is a prime number

 37 is a prime number

 41 is a prime number

 43 is a prime number

 47 is a prime number

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C PROGRAM FOR ARMSTRONG NUMBER

/*  C PROGRAM FOR  ARMSTRONG NUMBER */

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

     int s,x,i,n;

     clrscr();

     printf("\n\t\tARMSTRONG NUMBER");

     printf("\n\t\t~~~~~~~~~~~~~~~~");

     printf("Armstrong no's are\n");

       for(i=100;i<=1000;i++)

      {

         s=0;

         x=i;

          while(x>0)

          {

              n=x%10;                      

              x=x/10;                  

               s+=pow(n,3);             

           }                       

            if(i==s)                

            printf("%d\n\n",i);     

       }                       

     getch();

}                     

             

OUTPUT:

ARMSTRONG NUMBER

  

 Armstrong no's are:

153

370

371

407

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